Question

3. The length, breadth and height of a mom are 825 cm. 675 cm and 450 cm respectively
Find the longest tape which can measure the three dimensions of the womexactly
wine the smallest 3-digit number which is exactly divisible by 0.8 and 12.​

Answer 1

75 cm

Step-by-step explanation:

• To find the length of the longest tape which can measure the three dimensions of the room, we need to find the H.C.F of length, breadth and height of the room respectively.

=> Length of the room = 825 cm

=> Breadth of the room = 675 cm

=> Height of the room = 450 cm

• Let us factorize all three given dimensions.

=> 825 = 3 × 5 × 5 × 11

=> 675 = 3 × 3 × 3 × 5 × 5

=> 450 = 2 × 3 × 3 × 5 × 5

• Hence, 3, 5 and 5 are the common prime factors here.

=> So, H.C.F =3 × 5 × 5

=> H.C.F = 75 cm

=> Therefore, we need 75 cm the longest tape to measure the three dimensions of the room.

Answer 2

Answer:

find the length of the longest tape which can measure the three dimensions of the room, we need to find the H.C.F of length, breadth and height of the room respectively.

Length of the room = 825 cm

Breadth of the room = 675 cm

Height of the room = 450 cm

Let us factorize all three given dimensions.

825 = 3 × 5 × 5 × 11

675 = 3 × 3 × 3 × 5 × 5

450 = 2 × 3 × 3 × 5 × 5

Hence, 3, 5 and 5 are the common prime factors here.

So, H.C.F =3 × 5 × 5

H.C.F = 75 cm

Therefore, we need 75 cm the longest tape to measure the three dimensions of the room.