Question

3. The length l’of a rectangular field is thrice more than its breadth 'b'. Its perimeter is
400 meters. Find its dimensions.​

Answer 1

$\huge\star{\green{\underline{\mathfrak{Answer :-}}}}$

Length = 300 m and breadth = 100 m.

$\huge\star{\green{\underline{\mathfrak{Explanation :-}}}}$

Length of the rectangular field = l.

Breadth of the reactangular field = b.

ATQ,

$l = 3b$

$l - 3b = 0$

.....Eqn 1

ATQ,

perimeter = 400 meters

$2(l + b) = 400$

$l + b = 200$

$l + b - 200 = 0$

.....Eqn 2

Solving pair of linear equations in two variables with substitution method....!!!

From Eqn 1 ,

$l = 3b$

Putting this value in Eqn 2 ,

$3b - b - 200 = 0$

$2b = 200$

$b = 100$

Therefore, breadth of the rectangular field = 100 m.

Length =

$l = 3b = 3 \times 100 = 300 \: m$

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