Question

3 The length of a rectangle exceeds its width by 4 m. If its perimeter is 40 m, find its dimensions
ridh

1​

Answer 1

$\begin{gathered} \\ \Large{\bf{\green{\underline{AnSwEr\::}}}} \\ \end{gathered}$

• Length of the rectangle = 12 m

• Breadth of the rectangle = 8 m

$\begin{gathered} \\ \Large{\bf{\red{\underline{GiVeN\::}}}} \\ \end{gathered}$

• Perimeter of rectangle = 40 m

• Breadth of rectangle = x m

• Length of rectangle = x + 4 m

$\begin{gathered} \\ \Large{\bf{\purple{\underline{To \: FiNd\::}}}} \\ \end{gathered}$

• Dimensions of the rectangle

$\begin{gathered} \\ \Large{\bf{\pink{\underline{SoLuTiOn\::}}}} \\ \end{gathered}$

Perimeter of rectangle = 2 ( length + breadth )

⇒ 40 m = 2 ( x + 4 + x )

⇒ 40 m = 2 ( 2x + 4 m )

⇒ 20 m = 2x + 4 m

⇒ 2x = 20 m - 4 m

⇒ 2x = 16 m

⇒ x = 16 m ÷ 2

⇒ x = 8 m

Length of the rectangle = x + 4 = 8m + 4m = 12 m

Breadth of rectangle = x = 8 m

Answer 2

$\huge\sf\underline\red{QuestioN}::-$

Length of a rectangle exceeds its breadth by 4 m. If the perimeter of the rectangle is 40 m, find its length and breadth.

$\huge\sf\underline{GiveN}::-$

Breadth of rectangle = 8cm

Length of rectangle = 12cm

Perimeter of Rectangle = 40cm

$\huge\sf\underline\purple{To \: Find}::-$

Dimensions of Rectangle?

$\huge\sf\underline\green{Solution}::-$

Let the breadth be x

And length be x + 4

.

Perimeter = 2(Length + Breadth)

$\longrightarrow 40 = 2(x + 4 + x)</p><p> \\ \longrightarrow 40 = 2(2x + 4) \\ \longrightarrow \frac{40}{2} = (2x + 4) \\ \longrightarrow20 = 2x + 4 \\ \longrightarrow20 - 4 = 2x \\ \longrightarrow16 = 2x \\ \longrightarrow \frac{16}{2} = x \\ \huge \longrightarrow \sf \fbox \red 8$

Length of rectangle

=> x + 4

=> 8 + 4

=> 12.

Breadth of Rectangle = x

=> 8m

$\therefore \sf \: Length \: of \: rectangle = \red {12meters}</p><p> \\ \sf \ Breadth \: of \: rectangle = \red {8meters }$