3) The length of a steel measuring tape was found to be 50 m at a
temperature of 25°C. What will be the change in length if the
temperature rises to 40°C. Given a = 1.2 x 10-50c-1.
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Answer:
The scale is calibrated at 200C
At 400C , the measuring gaps will be more. So, it will measure lesser than the actual.
Using, l2=l1(1+αdt) where α=10−5, dt = 20 and l1 = 5, we get l2 = 5.001m
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