Question

3) The length of an aluminium rod at the temperature 303 K is 50m. What would be its
increase in length when it is heated to 323 K ? ( The linear co-efficient of Aluminiun
23 X 10K)​

Answer 1

Answer:

If you find this helpful, you can follow me. Thanks

Explanation:

$\alpha = \: \frac{l2 \: - \: l1}{l \: \times temperature}$

Use this formular

$increase \: in \: length \: = l2 \: - \: l1$

Thats what you're solving for

$parameters \\ \alpha = 23 \times {10}^{?} {k}^{ - 1} \\ temperature \: = \: 303k \\ l \: = \: 50m$