Math, asked by matterclose, 11 months ago

3. The lengths of diagonals of a rhombus are 30 cm and 40 cm. Find the side of the
rhombus.​

Answers

Answered by khanpathan786
0

Answer:

(d1/2)^2+(d2/2)^2=side^2

=(30/2)^2+(40/2)^2=side^2

=15^2+20^2=side^2

=225+400=side^2

=625=side^2

=√625=side

=25cm

Answered by Anonymous
30

 \huge \underline \mathbb {SOLUTION:-}

As diagonals of a rhombus are equal and cut each other at right angle.

  • Figure provided in the above attachment.

Using Pythagoras theorem:

AD² = AO2² + OD²

➠ AD² = (30/2)² + (40/2)²

➠ AD² = 15² + 20²

➠ AD² = 225 + 400

➠ AD² = 625

➠ AD = √625

AD = 25 cm

  • So, side of the rhombus is 25 cm.

\setlength{\unitlength}{1.0 cm}}\begin{picture}(12,4)\thicklines\put(1,1){\line(1,0){6.5}}\put(1,1.1){\line(1,0){6.5}}\end{picture}

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