Math, asked by tharunkumarreddy25, 1 year ago


3. The liquids, X and Y are mixed in
the ratio of 3:2 and the mixture
is sold at Rs. 11 per litre at a
profit of 10%. If the liquid X costs
Rs. 2 more per litre than Y, the
cost of X per litre is (in Rs.) :
(1) 10.80 (2) 11.75
(3) 9.50
(4) 11​

Answers

Answered by Aniketdhayal
2

Answer:

(1) 10.80

I hope this is help full you


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Answered by rajeshsaini0
1

Answer:

Step-by-step explanation:

Description for Correct answer:

X:Y

Quantity 3:2=5units

SP of 1 unit=Rs. 11

SP of 5 units=Rs. 55

CP of 1 unit=Rs. 10

then CP of 5 units=Rs. 50

Let

Y's cost = z Rs.

X's cost = z+2 Rs.

CP=Quantity×Cost

50=3(z+2)+2z

50=3z+6+2z

z=8.80 Rs.

Cost of X=8.80+2=10.80 Rs.

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