Question

3. The man of the numbers is 40. An the three numbers are different
natural numbers. If west 19. what could be highest possible
number of remaining two numbers?
h) 10
(e) 100
d) 71
please give answer I will mark it brainliest​

Answer 1

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Answer:

10 is the answer

Step-by-step explanation:

As it is given in the question the sum of all natural numbers is 40

One of the number is 19

Therefore the sum of remaining three natural numbers is 21

So 10 will be the answer as other number are greater than 21

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