3. The mean of 40 observations was 160. It was detected on rechecking that the value 165
was wrongly copied as 125 for computation of mean. Find the correct mean.
Answers
The correct mean of the required observations is 161. = > 6400 = sum of 40 observations. Later on, it was detected on rechecking that the value of 165 was wrongly copied as 125 for computation of mean. Hence, the correct mean is 161.
Here,
Here,n=40,
Here,n=40, X
Here,n=40, X =160
Here,n=40, X =160So,
Here,n=40, X =160So, X
Here,n=40, X =160So, X =
Here,n=40, X =160So, X = n
Here,n=40, X =160So, X = n1
Here,n=40, X =160So, X = n1 (∑x
Here,n=40, X =160So, X = n1 (∑x i )
Here,n=40, X =160So, X = n1 (∑x i )160=
Here,n=40, X =160So, X = n1 (∑x i )160= 40
Here,n=40, X =160So, X = n1 (∑x i )160= 401
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x ∑x
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x ∑x i =6400
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x ∑x i =6400Therefore, incorrect value of ∑x
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x ∑x i =6400Therefore, incorrect value of ∑x i=6400
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x ∑x i =6400Therefore, incorrect value of ∑x i=6400Now,
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x ∑x i =6400Therefore, incorrect value of ∑x i=6400Now,Correct value of ∑x
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x ∑x i =6400Therefore, incorrect value of ∑x i=6400Now,Correct value of ∑x i =6400−125+165=6440
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x ∑x i =6400Therefore, incorrect value of ∑x i=6400Now,Correct value of ∑x i =6400−125+165=6440Therefore,
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x ∑x i =6400Therefore, incorrect value of ∑x i=6400Now,Correct value of ∑x i =6400−125+165=6440Therefore,Correct mean = 40
Here,n=40, X =160So, X = n1 (∑x i )160= 401 (∑x ∑x i =6400Therefore, incorrect value of ∑x i=6400Now,Correct value of ∑x i =6400−125+165=6440Therefore,Correct mean = 406440 =161
Answer:
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Step-by-step explanation:
ANSWER
Here,
n=40,
X
=160
So,
X
=
n
1
(∑x
i
)
160=
40
1
(∑x
i
)
∑x
i
=6400
Therefore, incorrect value of ∑x
i
=6400
Now,
Correct value of ∑x
i
=6400−125+165=6440
Therefore,
Correct mean =
40
6440
=161