Question

3. The median for the following distribution is 26. Find the missing
frequency
C.I
f
0-10
3
10-20 20-30
5
30-40
6
40-50
4​

Answer 1

Answer:

please follow me

Step-by-step explanation:

9

2

=9×9=81

similarly,

12

2

=12×12=144

Hence, D is the correct option.

Answer 2

Step-by-step explanation:

N=18+A

M= Size of (N/2)th value

M=size of (18+A/2)th value

M=size of (9+A/2)th value

LCF 8+A is greater or equal to 9+A/2

therefore the median class is. 20-30

given

l=20

pcf =8

f=A

h=10

N/2=18+A/2

M=26

M= l+h/f [N/2-pcf ]

26=20+10/A[18+A/2-8]

26-20= 10/A[18+A-16/2]

6A=10[2+A/2]

6A=[20+10A/2]

12A=20 +10A

2A=20

A=10

THEREFORE THE MiSSING FREQUENCY IS 10