Question

3.) The outer orbitals of C in ethene molecule can be
considered to be hybridized to give three equivalent
sp² orbitals. The total number of sigma and pi
bonds in ethene molecule is
(1) 1 sigma (0) and 2 pi (at) bonds
(2) 3 sigma (0) and 2 pi (1) bonds
(3) 4 sigma (o) and 1 pi (Tt) bonds
(4) 5 sigma (o) and 1 pi (Tt) bonds​

Answer 1

ANSWER :-

The correct option is : (c) 5 sigma (σ) and 1 Pi (π) bonds .

Answer 2

Answer:

$\large\boxed{\sf{(4)\:5\:sigma\:(\sigma)\:and\:1\:pi\:(\pi)\:bonds}}$

Explanation:

We know that the molecular formula of Ethene is $\bold{C_{2}H_{4}}$.

Also, each carbon in ethene molecule is $\bold{s{p}^{2}}$ hybridised, that is it gives three equivalent $s{p}^{2}$ orbitals .

Now we have to find the total number of sigma and pi bonds in ethene molecule.

$\red{Note:-} Refer \: to \: the \: attachment.$

In the attached figure, we can see the structure of ethene molecule.

We know that one Carbon is singly bonded to two hydrogen atoms and both carbons are attached to each other with double bond.

Also, we know that, in double bond, one bond is sigma and other bond is pi.

And, in single bond, the bond is sigma.

So, there are total 5 sigma bonds and 1 pi bond.

Hence, the correct option is,

$\bold{\sf{(4)\:5\:sigma\:(\sigma)\:and\:1\:pi\:(\pi)\:bonds}}$