Math, asked by wwwanu4233, 3 months ago

3. The perimeter of a rectangle is 50 m and its breadth is 12 m. Find its:
(1) length
(i) area​

Answers

Answered by MasterDhruva
22

Given :-

Perimeter of the rectangle :- 50 metres

Breadth of the rectangle :- 12 metres

To Find :-

Length and area of the rectangle.............

Formula required :-

Length :-

{\large \tt \dashrightarrow \orange{\boxed{\tt \gray{\dfrac{Perimetre}{2} - Breadth}}}}

Area :-

{\large \tt \dashrightarrow \orange{ \boxed{\tt \gray{Length \times Breadth}}}}

Solution :-

First, we should find the length of the rectangle because to find area both length and breadth are necessary..............

Length of the rectangle :-

{\tt \longrightarrow \dfrac{50}{2} - 12}

{\tt \longrightarrow \cancel \dfrac{50}{2} - 12 = \boxed{\tt 25 - 12}}

{\tt \longrightarrow 13 \: \: Metres}

Now,

Area of the rectangle :-

{\tt \longrightarrow 13 \times 12}

{\tt \longrightarrow 156 \: \: Metres^{2}}

\Huge\therefore The length of the rectangle is 13 metres and area of the rectangle is 156² metres.

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\dashrightarrow Some related formulas :-

Breadth (rectangle) :-{\boxed{\sf\dfrac{Perimetre}{2} - Length}}

Perimeter (rectangle) :-{\boxed{\sf 2 (length+breadth)}}

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More to know..................

  • Rectangle is a 4-sided, 2-D figure. The finding of area and perimeter of the rectangle is a sum in mathematics. It is a shape which has the opposite sides equal. The finding of area and perimeter of rectangle and many other figures is very useful in our daily lives.
  • Finding the perimeter of rectangle is used when the park is being fenced or the house is getting a boundary etc......
  • Finding the area of the rectangle is used when the park is being tiled or the floor of the house is getting mat on it.
Answered by Anonymous
97

Question :-

The perimeter of a rectangle is 50 m and its breadth is 12 m. Find its:

(1) length

(2) area​

Given :-

  • Breath = 12 meters

  • Perimeter of rectangle = 50 meters

Formulas to find solution  :-

\boxed{\mathsf{Area\:of\:rectangle\:=\:Length\:\times\:Breath}}

\boxed{\mathsf{perimeter\:of\:rectangle\:=\:2(Length\:+\:Breath)}}

Solution 1 :-

  • Here we will use Perimeter of rectangle to find length .

  • Let length be x

\mathsf{:\longrightarrow\:Perimeter\:of\:rectangle\:=\:2(Length\:+\:Breath)}

\mathsf{:\longrightarrow\:50\:=\:2(x\:+\:12)}

\mathsf{:\longrightarrow\:\dfrac{50}{2} \:=\:x\:+\:12}

  • now by cuting fraction by the multiple of 2 we get 25

\mathsf{:\longrightarrow\:25 \:=\:x\:+\:12}

\mathsf{:\longrightarrow\:25\:-\:12 \:=\:x}

\mathsf{:\longrightarrow\:13\:=\:x}

  • Now put the value of x = 13
  • as we know we take the length be x

Length = x = 13 meters

  • LENGTH = 13 meters

__________________________________________________

Solution 2 :-

  • Here we have length and breath so now we will use formula of area of rectangle .

\mathsf{:\longrightarrow\:Area\:of\:rectangle\:=\:Length\:\times\:Breath}

\mathsf{:\longrightarrow\:Area\:of\:rectangle\:=\:13\:\times\:12}

\mathsf{:\longrightarrow\:Area\:of\:rectangle\:=\:156\:m^{2} }

Final answer :-

Solution 1 :-

\boxed{\mathsf{\:Length\:13\:m}}

Solution 2 :-

\boxed{\mathsf{Area\:of\:rectangle\:=\:156\:m^{2}}}


Anonymous: Impressive ^^
Anonymous: Thank you sis :)
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