Question

3. The perimeter of a rectangle is 50 m and its breadth is 12 m. Find
(I)length
(ii) area
​

Answer 1

☆ Solution ☆

Given :-

• The perimeter of a rectangle is 50 m.
• The breadth of rectangle is 12 m.

To Find :-

• The length of rectangle
• The area of rectangle

Step-by-Step-Explaination :-

As we know that :-

Perimeter of rectangle = 2 ( l + b )

Where,

• Perimeter of rectangle = 50 m

• Breadth of rectangle = 12 m

Let,

• Let the length be l

Putting the respective value,

50 = 2 ( l + 12 )

50/2 = l + 12

25 = l + 12

l = 25 - 12

l = 13

Thus,

Length of rectangle = 13 m

Now,

As we know that :-

Area of rectangle = l × b

Where,

• Length of rectangle = 13 m

• Breadth of rectangle = 12 m

Putting the respective value,

Area of rectangle = 13 × 12

Area of rectangle = 156 m²

Thus,

Area of rectangle = 156 m²

Answer 2

Answer:

$\huge\underline\mathfrak\red{♠question♠}$

the perimeter of a rectangle is 50 m and its breadth is 12.

find:- length

area

$\huge\underline\mathfrak\pink{♣Answer♣}$

let's find length of the rectangle:-

perimeter of rectangle is 2(l+b)

$50 = 2(l + b)$

$50 = 2l + 24$

$2l = 50 - 24$

$2l = 26$

$l = \frac{26}{2}$

$l = 13$

hence the length of the rectangle is 13m

now find the area of rectangle

using formula:-

area of rectangle is (l×b)

Area= 13×12

area = 156m²

hence area of rectangle is 156m

==>>length of rectangle= 13m

==>>area of rectangle= 156m²