Question

3) The perimeters of five squares are 24cm 32cm 40cm 76cm and 80cm respectively. The
perimeter of another square equal to area to sum of areas of these squares is?
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Answer 1

Answer:

124cm

Step-by-step explanation:

Side of the squares are 6 cm, 8 cm, 10 cm, 19 cm and 20 cm respectively.

Sum of their areas =\left ( 6^{2}+8^{2}+10^{2}+19^{2}+20^{2} \right ) cm^{2}

= (36 + 64 + 100 + 361 + 400) cm^{2}

= 961 cm^{2}

∴ Area of largest other square = 961 cm^{2}

= Its side = \sqrt{961} = 31 cm

∴ Required perimeter = 4 \times 31 = 124 cm.