Question

3. The point on the x-axis which is equidistant from the points (2,-5) and (-2,9) is
a) (-7, 0)
b) (0, -7)
c) (7,0)
d) (0,7)​

Answer 1

Answer:

the answer is tjis (-7, 0)

Answer 2

Solution :

Given points : A (2,-5) and B (-2,9)

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Let points be P (x,0)

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So, AP = BP also AP² = BP²

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(x-2)² + (0+5)² = (x + 2)² + (0-9)²

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↦ x² + 4 - 4x + 25 = x² + 4x + 4x + 81

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↦ x² + 29 - 4x = x² + 85 + 4x

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↦ -4x - 4x = 85 - 29

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↦ -8x = 56

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↦ x = -7

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So, correct opt is (-7,0)