(3) the polynomial (x − a), where a>0, is a factor of the polynomial q(x) = 4√2x 2 − √2. Which of these is a polynomial whose factor is (x − 1 a ) ?
Answers
Answer:
x2+x-6
Step-by-step explanation:
See the Image attached
Given: The polynomial (x-a), where a>0 , is a factor of the polynomial q(x) = 4√2x²-√2.
To Find : Which of these is a polynomial whose factors is ( x -1/a) ?
a) x²+x+6
b) x²+x-6
c) x²-5x+4
d) x²+4x-3
Solution:
q(x) = 4√2x²-√2.
(x-a) is factor
=> q(a) = 0
=> 4√2a²-√2 = 0
=> 4a² - 1 = 0
=> (2a + 1) (2a - 1) = 0
=> a = -1/2 , 1/2
a > 0
Hence a = 1/2
=> 1/a = 2
x -1/a = x - 2
x²+x+6 for x = 2 value is 2² + 2 + 6 = 12 ≠ 0
x²+x-6 = (x + 2)(x - 2) Hence x - 2 is a factor
or x = 2 => 2² + 2 - 6 = 0
x²-5x+4 = (x - 4)(x - 1) hence x - 2 is not a factor
x²+4x-3 = 2² + 4(2) - 3 = 9 ≠ 0
x²+x-6 is the correct answer
Learn More:
Factorize 4(x2+7x)2–8(x2+7x)(2x-1) + 4(2x-1)2 - Brainly.in
brainly.in/question/18251756
find the value of x by factorization, x2-8x+1280=0 - Brainly.in
brainly.in/question/7343350
8. Factorize 6n² -1 -2. If the factors are the measures of sides of a ...
brainly.in/question/18645339