Question

3. The present ages of Mohit and Mayank are in the ratio 11:8. After 8 years, the ratio of their ages will
be 5.4. Find their present ages
​

Answer 1

Answer:

Mohit age=22years & Mayank age =16years

Step-by-step explanation:

Let, the common multiple is x

Ratio of thier present age 11:8

Present age of mohit and mayank is 11x & 8x years.

After 8year ratio of their ages is 5:4

Now, 11x+8/8x+8=5/4

Take cross multiplication

44x+32=40x+40

44x+32-40x-40=0

4x- 8=0

x=8/4

x=2

The age of mohit 11x =11×2=22years

The age of Mayank 8x=8×2=16years

Answer 2

There is minor mistake in this question ;

Correct Question:

The present ages of Mohit and Mayank are in the ratio 11:8. After 8 years, the ratio of their ages will be 5 : 4. Find their present ages ?

Answer:

• The present age of Mohit's = 22 year's

• The present age Mayank's = 16 year's

Given :

• The present ages of Mohit and Mayank are in the ratio 11:8.

• After 8 years, the ratio of their ages will be 5 : 4.

To find :

• Their present ages =?

Step-by-step explanation:

Let, The present age of Mohit's be 11x.

Then, the present age Mayank's be 8x.

After 8 year's Mohit's age = 11x + 8

After 8 years Mayank's age = 8x + 8

According to the given question :

➟ (11x + 8)/(8x+8) = 5/4

➟ 4(11x+8) = 5(8x+8)

➟ 44x + 32 = 40x + 40

➟ 44x - 40x = 40 - 32

➟ 4x = 8

➟ x = 8/4

➟ x = 2

Hence,

The present age of Mohit's = 11x => 11 × 2 = 22 year's

The present age Mayank's = 8x => 8 × 2 = 16 year's