Question

3. The principle value of sin-1 (V3/2) is
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Answer 1

Answer:

The answer is $\dfrac{\pi}{3}$

Step-by-step explanation:

•     Since we know that principal branch of $\sin^{-1}x$ is $[-\dfrac{\pi}{2},\dfrac{\pi}{2}]$ and                   $\sin\dfrac{\pi}{3}=\dfrac{\sqrt 3}{2}$

   $\therefore \sin^{-1}\dfrac{\sqrt 3}{2}=\dfrac{\pi}{3}$