Question

3) The radius of a circle with centre P i 25cm. The length
of the same circle is 48 cm an find the distance
of the chard from the centre p
the​

Answer 1

Step-by-step explanation:

$\bf{Here \: We \: Go!!}$

GIVEN:-

=> AB=48 cm is a chord of the circle with centre P.

=>Radius = r = 25 cm.

=>PN is the perpendicular distance of AB from P.

TO FIND:-

=>The distance of the chord from centre P of the circle.

UNDERSTANDING THE CONCEPT:-

According to the question,

=>We know that a chord of a circle is bisected by the line which is the perpendicular distance of the chord from the centre of the given circle.

=> From this we can find the distance of the chord.

$\huge\tt\fbox\purple{Answer}$

=> From the above concept we came to know that,

$\bf{AN = BN}$

$\bf{ = > \dfrac{48}{2}cm = > 24cm }$

So, After this,

=>In ΔPAN, ∠PNA is a right angle.

=>ΔPAN is a right one with hypotenuse as PA.

=>As it is right angle we should apply Pythagoras theorem.

As a result,

$\bf{ = > \sqrt{pa {}^{2} - an {}^{2} } }$

$\bf{ = > \sqrt{25 {}^{2} - 24 {}^{2} } }$

$\bf{ = > 7cm}$

Therefore, the distanceof the chord from centre P of the circle is 7cm.