Question

(3) The roots of x² + kr + k = 0 are real and equal, find k.

(A)0
(B) 4
(C) 0 or 4
(D) 2​

Answer 1

Answer:-

Given:

Correct option : C

${x}^{2} + kx + k$

roots are real and equal

${b}^{2} - 4ac = 4$

${k}^{2} - 4(1)(k) = 0$

${k}^{2} - 4k = 0$

$k(k - 4) = 0$

$.k = 0 \: or \: k = 4$

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Answer 2

Answer:

Two real and equal roots means that the discriminant of the equation is zero.

${b}^{2} - 4ac = 0$

Putting a = 1, b = k and c = k

${k}^{2} - (4)(1)(k) = 0$

$k(k - 4)= 0$

Either k = 0 or k = 4

Hence, Option (C) is correct.

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