Question

3. The shape of a garden is rectangular in the middle and semicircular
at the ends as shown in the diagram. Find the area and the perimeter
T of this garden (Length of rectangle is
7 m 20 - (3.5+3.5) metres)
D
20 m
tile has the shane of a narallelogram whose
marallelogram whose base is 24 cm and​

Answer 1

Answer:

breadth ⇒ 7m

lenghth ⇒20m (3.5 + 3.5)m

             ⇒20m -7m ⇒13m

area of the garden

⇒ area of rectangle + area of semicircle

⇒length×breadth +(2×1/2×πr²)

⇒13×7 +( 2×1/2×22/7×3.5 ×3.5 )

⇒13×7+(22×0.5×3.5)

⇒91+38.5 ⇒129.5

perimeter of garden

⇒perimeter of 2 semi circle + 20m +20m

⇒2πr + 13m + 13m

⇒2×22/7 ×3.5/10 + 13m +13m

⇒22+13m+13m ⇒22 +26m ⇒48m

∴ area of garden⇒ 129.5m²

∴perimeter of garden ⇒ 48m

Step-by-step explanation:

Answer 2

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Total area of the garden = Area of the rectangular portion + The sum of the areas of the pair of semi-circles

$l.b + 2 \times \frac{1}{2}\pi {r}^{2}$

$= (13 \times 7) {m}^{2} +$

$(2 \times \frac{1}{2} \times \frac{22}{7} \times 3.5 \times 3.5) {m}^{2}$

$= (91 + 38.5) {m}^{2} = 129.5 {m}^{2}$

Perimeter of the garden =2× length of rectangular portion + circumference of the circle

$= (2 \times 13 + 2 \times \frac{22}{7} \times 3.5)m$

$= (26 + 22)m = 48m$