Question

3. The slope of tangent to the curve y=x²-6x + 3 at point (6,3) is​

Answer 1

SOLUTION

TO DETERMINE

The slope of tangent to the curve y = x²-6x + 3 at point (6,3)

EVALUATION

Here the given equation of the curve is

y = x² - 6x + 3

Differentiating both sides with respect to x we get

$\displaystyle \sf{ \frac{dy}{dx} = 2x - 6 }$

Hence the required slope of tangent to the curve y = x²-6x + 3 at point (6,3) is

$\displaystyle \sf{m = \frac{dy}{dx} \bigg| _{(6,3) } }$

$= (2 \times 6) - 3$

$= 12 - 3$

$= 9$

FINAL ANSWER

The slope of tangent to the curve

y = x²-6x + 3 at point (6,3) is 9

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Answer 2

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