Math, asked by Dilipsinghkushwaha46, 8 months ago

3. The smallest number of 4-digits which when
divided by 6, 8, 12 and 20 leaves remainder 5
in each case is :
(A) 1285
(B) 1200
(C) 1085
(D) 1080

Answers

Answered by prakashd8770

2

Answer:

1085 answer correct follow and like me

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