Question

[3] The sum of a two digit number and the number obtained by interchanging the digits is 121. The at the unit place is 7 more than the digit
at the tens place. find the number​

Answer 1

Answer:

29

Step-by-step explanation:

Let the number be 10x+y.

Thus, the number obtained by interchanging the digits will be 10y+x.

From the first condition,

(10x+y)+(10y+x) = 121

11x+11y = 121

x+y = 11 ...(1)

From the second condition,

y=x+7 ...(2)

Put y=x+7 in equation (1),

x+y=11

x+x+7=11

2x+7=11

2x=4

x=2

Put value of x in equation (2),

y=x+7

y=2+7

y=9

Therefore,

10x+y = 10×2+9

= 20+9

= 29.

Ans. The required number is 29.

Answer 2

Answer

29

I've solved using a different method

mark me as brainliest if it helps