Question

3. The sum of digits of a two-digit number is 17
On reversing its digits, the new number is 9
more than the original number Find the
number.​

Answer 1

Step-by-step explanation:

Hello your answer will be 89.

Its sum is 17

When it is reversed it becomes 98 which is 9 more than 89

Answer 2

Answer:

$\huge{\boxed{\rm{\red{ answer=89}}}}$

Step-by-step explanation:

Given:-

The sum of digits of a two-digit number is 17

On reversing its digits, the new number is 9

its digits, the new number is 9more than the original number .

To find:-

Find the number.

Solution:-

Let the digits be X and Y.

Let the digit at one's place= Y

and at 10's place =X

Then, The number =10X+Y

if the digits are reversed then the number

=10Y+X

According to the given problem,

1)The sum of digits =17

= X+Y=17....(1)

=X=17-Y....(2)

On reversing its digits, the new number is 9

reversing its digits, the new number is 9more than the original number.

=>10Y+X=10X+Y+9

=>10Y+X-10X-Y=9

=>9Y-9X=9

=>9(Y-X)=9

=>Y-X=9/9

=>Y-X=1

=>Y-(17-Y)=1

=>Y-17+Y=1

=>2Y-17=1

=>2Y=1+17

=>2Y=18

=>Y=18/2

=>Y=9

and X=17-9=8

Then the number =10X+Y=10(8)+9=80+9=89

Answer:-

The original number =89