Question

3) The sum of number and its squre is
42 find the number.​

Answer 1

Answer:

6 and -7

Step-by-step explanation:

hope it is helpful

Answer 2

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• The sum of number and it's square is 42. Find the number.

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Let the number be $x$

Therefore, according to the give condition,

$x + {x}^{2} = 42$

$\implies {x}^{2} + x - 42 = 0$

$\implies {x}^{2} + 7x - 6x- 42 = 0$

$\implies x(x + 7) - 6(x + 7) = 0$

$\implies (x - 6)(x + 7) = 0$

Therefore, either $(x-6)=0$ or $(x+7)=0$

So,

$x - 6 = 0$

$\implies x = 6$

Also,

$x + 7 = 0$

$\implies x = - 7$

$\star\:\:\:\bf\large\underline\blue{Answer:-}$

• The number may be -7 or 6.