Question

3) The sum of the digits of a two- digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits.
Find the number. ​

Answer 1

Answer:

18 is your answer

Step-by-step explanation:

9×9=18÷2=9

Answer 2

18

Step-by-step explanation:

Let the ten's digit no. be x

And one's digit no. be y.

So the no. will be = 10x+y.

Given :

x+y=9-----(I)

9(10x+y)=2(10y+x)

⇒88x−11y=0 -----(II)

On solving I and II simultaneously you will get x=1 and y=8.

Therefore your desired no. is 18.