Question

3) The sum of the present ages of elder 1 д Sister is 28 years and the Profuct of of their the present ages and younger ages is is 187 find the present age.
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Answer 1

Answer:

let the age of the brother be x and age of the sister be y.

now x+y=21 (given)…….1

five years ago

the age of brother is x-5 and age of sister is y-5

therefore (x-5)(y-5)=28(given)

(x-5)(21-x-5)=28(from 1)

x^2–21x+108=0

(x-9)(x-12)=0

x=9 or x=12

therefore y=12 or y=9

the brother’s and sister’s age can be 9,12 and 12,9 respectively