Question

3. The sum of three consecutive multiples of 11 is 363. Find these multiples.

4.The different between two wholenumbert is 66. The ratio of the the numbers is? What are the two​

Answer 1

3 •

Let the three consecutive multiples be x , 11 + x and 22 + x

adding them ==> 3x + 33 = 363
canceling 3

x + 11 = 121
x ==> 121-11 ==> 110


thereforr multiples are 110,121,132


4• i dont think the question is complete

Answer 2

Answer:

Let the first consecutive multiple of 11 be x

Then, second consecutive multiple of 11

= x + 11

& third consecutive multiple of 11

= x + 11 +11

according to question,

x + x+ 11 + x + 11 + 11 = 363

or, 3x + 33 = 363

or, 3x = 363 - 33

or, 3x = 330

or, x = 330/3

x = 110

Therefore, the first no. = x = 110

second no. = x+11 = 110+11 = 121

third no. = x+11+11 = 110+22 = 132