Question

3. The sum of three consecutive numbers is 48. Find the numbers.​

Answer 1

Answer:

Let the first number be x.

According to the question,

$= > x + x + 1 + x + 2 = 48 \\ = > 3x + 3 = 48 \\ = > 3x = 48 - 3 \\ = > 3x = 45 \\ = > x = \frac{45}{3} \\ = > x = 15.$

Therefore, the three consecutive integers are - 15,15+1=16,15+2=17.

Answer 2

$\huge\bigstar\mathfrak\pink{\underline{\underline{SOLUTION:}}}$

Let the first number be x

then second number= x+1 &

third number= x+2

Given=48

A/q

=) x+x+1x+2= 48

=) 3x+3= 48

=) 3x= 48-3

=) 3x= 45

=) x= 45/3=15

=) x= 15

Hence,

The first number is 15.

The second number is, x+1= 15+1= 16.

Third number is, x+2= 15+2= 17.

So, Numbers are 15,16 &17

hope it helps ☺️