Question

3. The sum of two angles of a triangle is 90° and
their difference is 30°. Find the three angles of the
triangle.​

Answer 1

$\huge\green{A}\red{N}\orange{S}\pink{W}{E}\blue{R}$

Let the two angles be a,b

So

a+b=90

a-b=30

From the first equation, we can say that,

a=90-b

We will substitute this in second equation

a-b=30

90-b-b=30

90-2b=30

-2b=30-90

-2b= -60

2b=60

b=30

a+b=90

a+30=90

a=90-30

a=60

a+b+c=180

60+30+c=180

90+c=180

c=90

So,

$\huge\boxed{\red{a=60,b=30,c=90}}$

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Answer 2

Answer:

60° , 30° , 90°

Step-by-step explanation:

let the two angle be x & y ,where let x > y

then

x + y = 90° -----(i)

also it's given that

x - y = 30° ----(ii)

so,on adding both equation ,we get :

x + y + x - y = 90° + 30°

2x = 120°

x = 60° -----(iii)

now on putting the value of x in equation (i),we

get :

60° + y = 90°

y = 30° ------(iv)

Therefore, x = 60°, y = 30°

the three angles are 60° , 30° and 90°.