3) The sum of two integers is -12. If one of them is 3 4) Find the largest 6-digit number divisible by 16. Bimoniu.
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Answer:
3) -15
4) 999,984
Step By Step Explanation:
3) Sum of two integers is -12. One of them is 3.
Let the another integer be x.
x + 3 = -12
x = -12 - 3
x = -15
4) The Largest 6 digit Number → 999999
When we divide it by 16, we get remainder as → 15
So, 999999 is greater than the number 15.
We subtract it from 999999
999999 - 15 = 999,984
→ Hence, 999,984 is exactly divisible by 16.
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