Math, asked by lawkumarsharma558, 7 hours ago

3) The sum of two integers is -12. If one of them is 3 4) Find the largest 6-digit number divisible by 16. Bimoniu.​

Answers

Answered by Anonymous
5

Answer:

3) -15

4) 999,984

Step By Step Explanation:

3) Sum of two integers is -12. One of them is 3.

Let the another integer be x.

\rightarrowtail x + 3 = -12

\rightarrowtail x = -12 - 3

\rightarrowtail x = -15

 \:

4) The Largest 6 digit Number → 999999

When we divide it by 16, we get remainder as → 15

So, 999999 is greater than the number 15.

\rightarrowtail We subtract it from 999999

\rightarrowtail 999999 - 15 = 999,984

Hence, 999,984 is exactly divisible by 16.

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