Question

"
3) The sum of two numbers is 8o and
the ratio is 3:5 find the greatest
amongest the two numbers​

Answer 1

Answer:

Step-by-step explanation:

Question :-

The sum of two numbers is 80. Their ratio is 3:5. Find the greatest numbers.

Given :-

Sum of two numbers = 80

Ratio of two numbers = 3 : 5

To Find :-

The greatest number.

Solution :-

Let the ratio be 3x and 5x .

⇒ 3x + 5x = 80

⇒ 8x = 80

⇒ x = 80/8

⇒ x = 10

1st Number =  3 × 10 = 30

2nd Number = 5 × 10 = 50

Hence, the greatest number is 50.

Verification :-

Sum of numbers = 80

⇒ 50 + 30 = 80

⇒ 80 = 80

Hence Verified.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Greatest\:number=50}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given :}} \\ \tt : \implies Sum \: of \: two \: number = 80 \\ \\ \tt : \implies Ratio = 3 : 5 \\ \\ \red {\underline \bold{To \: Find :}} \\ \tt: \implies Greatest \: numbers = ?$

• According to given question :

$\tt \circ \: Let \: number \: be \: x \: and \: y \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies x + y = 80 - - - - - (1)\\ \\ \bold{Ratio : } \\ \tt: \implies x: y = 3 : 5 \\ \\ \tt: \implies \frac{x}{y} = \frac{3}{5} \\ \\ \tt: \implies x = \frac{3y}{5} - - - - - (2) \\ \\ \text{Putting \: value \: of \: x \: in \: (1)} \\ \\ \tt: \implies \frac{3y}{5} + y = 80 \\ \\ \tt: \implies 3y + 5y = 80 \times 5 \\ \\ \tt: \implies 8y = 80 \times 5 \\ \\ \tt: \implies y = \frac{80 \times 5}{8} \\ \\ \green{\tt: \implies y = 50} \\ \\ \text{Putting \: value \: of \: y \: in \: (2)}\\ \tt: \implies x = \frac{3y}{5} \\ \\ \tt: \implies x = \frac{3 \times 50}{5} \\ \\ \green{\tt: \implies x = 30} \\ \\ \green{ \tt \therefore 50 \: is \: the \: Greatest \: number}$