Question

3) The surface area of
cuboid-shaped box having
length=80 cm,
breadth=40cm and
height=20cm is:​

Answer 1

Given ,

The dimensions of cuboid shaped box are

• Length = 80 cm
• Breadth = 40 cm
• Height = 20 cm

We know that , the total surface area of cuboid is given by

$\sf \fbox{TSA = 2(lb + bh + hl) }$

Thus,

$\sf \mapsto TSA = 2(3200 + 800 + 1600) \\ \\ \sf \mapsto</p><p>TSA = 2(5600) \\ \\ \sf \mapsto</p><p>TSA = 11200 \: {cm}^{2}$

$\therefore \sf \underline{The \: surface \: area \: of \: cuboid \: shaped \: box \: is \: 11200 \: \: {cm}^{2} }$

Answer 2

Answer:

The answer to the given question is The surface area of the cuboid-shaped box having

length=80 cm,

breadth=40cm and

height=20cm is: 11200 sq. cm

Step-by-step explanation:

Given :

length of the cuboid = 80 cm

the breadth of the cuboid = 40 cm

height of the cuboid= 20 cm

To find:

The surface area of the cuboid box.

Formula:

The formula to find the total surface area of a cuboid is

$2( lb+ bh +hl )$

Solution :

The cube is the 3D point of the rectangle, let us substitute the given values in the formula.

$2((80)(40) + (40)(20) + (80)(20))$

we can use simple mathematics here, the values inside the brackets should be multiplied.

$2(3200 + 800 + 1600)$

The values inside the brackets should be added.

$2(5600) =11200$

The final value obtained is 11200

The total surface area of the cuboid-shaped box is obtained as 11200 sq.cm.

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