Question

3. The total power dissipated in watt in the circuit
shown here is
​

Answer 1

Answer:

Total resistance(1/Rp)

=1/6+1/3+1/4=10/12=>Rp=12/10=1.2

V=IR

I=V/R=>I=18/1.2=15A

Power(P) =VI =>18*15=270W