Question

3. The two adjacent sides of a rectangle are 3a - b and 6b - a. Find its perimeter.
4. Find the perimeter of a triangle whose sides are 2y + 3z, 2 - y, 4y - 22.
5. Subtract:​

Answer 1

Answer:

3)P=2[(3a-b)+(6b-a) ]

=2(2a+5b)

4a +10b is the answer...

Step-by-step explanation:

4)(2y+3z) + (2-y) + (4y -22)

=(2y -y +4y)+(3z)+(2-22)

=5y+3z-20 is the final answer

Answer 2

Answer:

3 answer

perimeter of rectangle= 2(l+b)

=2(3a-b+6b-a)

=2(2a+5b)

=4a+10b

Step-by-step explanation:

4 answer

perimeter of triangle=sum of all sides

=2y+3z+2-y+4y-22

=5y+3z-20