Question

3. The two motor mechanics, Shyam and Ramu, working together can overhaul.
scooter in 6 hours. Shyam alone can do the job in 18 hours. In how many hours
a
lenk in the bottom in.
Ramu alone do it?​

Answer 1

Answer:

please give me the proper question

Answer 2

${ \large{ \sf{ \underbrace{\underline{\bigstar \:we\: know \:that, }}}}}$

$\sf{Number\: of \:hours \:Raju\: required \:to\: overhaul\: the\: scooter}$

$\bold\pink{\fbox{\sf{=\: 15\: hours}}}$

➦ Let us consider number of hours Sriraj to overhaul the scooter

$\bold\pink{\fbox{\sf{= X\: hours}}}$

➦ Number of hours required by Raju and Sriraj together to do piece of work = 6 hours

∴ We can calculate, work done by Raju in 1 hour

➦ 1/15 Work done by Sriraj in 1 hour

➦ 1/x Work done by both Raju and Sriraj in a hour

➦ 1/6 Work done by both Raju and Sriraj in 1 hour

$\sf{1/15 + 1/x = x+15/15x x+15/15x}$

$\sf{= 1/6 6x + 90 = 15x 9x}$

$\sf{= 90 x = 90/9 x = 10}$

${ \large{ \boxed{ \red{ \underline{ \bf \:∴ Sriraj\: can \:do \:the \:work\: in\: 10 }}}}}$

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