Question

3.
The value of frictional force on block in the given
diagram is (Take g = 10 m/s2)
m = 3 kg
mu = 0.3
(1) 4 N
(2) 5N
(3) 6N
(4) 9N​

Answer 1

Answer:

2) 5N

Explanation:

See the force = 5N, mu = 0.3 and mass is 3kg

N= mg here.

FS= usN = 0.3×30= 9.0.

Which is greater than the force.

But as we know static friction is self adjustable, the friction would limit itself to 5N only as it only needs to resist a force of 5N.

Answer 2

Given:

Mass of the block = 3 kg

Coefficient of friction, μ = 0.3

To Find: Frictional Force

Calculation:

The frictional force is a contact force. It is expressed as multiplication of normal force and coefficient of friction μ.

Normal force N = weight of object = mg = 3 * 10 = 30 N

Co-efficient of friction μ = 0.3

Frictional force = μ * N = 0.3 * 30 = 9 Newtons

Answer:

The frictional force is determined to be (4) 9 Newtons.