Question

(3)The value of (x - a)^3 + (x - b)^3 + (x - c)^3- 3 (x - a) (x - b) (x - c) when a+b+c= 3x is
(a) 3
(b) 2
(c) 1
(d)0​

Answer 1

Answer:

Step-by-step explanation:

$(x - a)^3 + (x - b)^3 + (x - c)^3- 3 (x - a) (x - b) (x - c)$

Let x-a=p,x-b =q and x-c=r

then p+q+r=x-a+x-b + x-c

=3x-(a+b +c)

=3x-3x=0

So p+q+r=0

Hence

p³+q³+r³=3pqr

Or p³+q³+r³-3pqr=0

Putting values of p,q and r we get