Question

3. The volume of a cuboidal box isx' + 14x' + 52x + 21 cubic units. Its height isx + 7 units. What is
its base area?

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Answer 1

Step-by-step explanation:

• Length of cuboid = (2x + 2) units

★

• Breadth of cuboid = (2x - 2) units

➪Height of cuboid = (2x - 2) units

➪Volume of cuboid is

$✵\sf\begin{gathered} Volume = Length \times Breadth \times Height\\\\ Volume = (\,2x + 2)\, \times (\,2x - 2)\, \times (\,2x - 2)\,\\\\ Volume = (\,(\,2x)\,^2 - (\,2)\,^2)\ \times (\,2x - 2)\,\\\\ Volume = (\,4x^2 - 4)\, \times (\,2x - 2)\, \\\\ Volume = 8x^3 - 8x^2 - 8x + 8\end{gathered}$

Answer 2

Answer:

Step-by-step explanation:

Length of cuboid = (2x + 2) units

★

Breadth of cuboid = (2x - 2) units

➪Height of cuboid = (2x - 2) units

➪Volume of cuboid is

\begin{gathered}✵\sf\begin{gathered} Volume = Length \times Breadth \times Height\\\\ Volume = (\,2x + 2)\, \times (\,2x - 2)\, \times (\,2x - 2)\,\\\\ Volume = (\,(\,2x)\,^2 - (\,2)\,^2)\ \times (\,2x - 2)\,\\\\ Volume = (\,4x^2 - 4)\, \times (\,2x - 2)\, \\\\ Volume = 8x^3 - 8x^2 - 8x + 8\end{gathered}\end{gathered}

✵

Volume=Length×Breadth×Height

Volume=(2x+2)×(2x−2)×(2x−2)

Volume=((2x)

2

−(2)

2

) ×(2x−2)

Volume=(4x

2

−4)×(2x−2)

Volume=8x

3

−8x

2

−8x+8