Question

3 The water in a measuring cylinder is at the 50 cm3 level. A pebble is dropped into the water and the water level rises to 60 cm3. The pebble is completely covered by water. calculate
the density of the pebble, if it weighs 60g​

Answer 1

Answer:

The density of the pebble is 6000 Kg/m³.

Explanation:

The volume of the water before immersing the pebble is 50 cm³. When the pebble is immersed in the water the volume rises to 60 cm³. According to Archimede's principle, the rise in the volume of the water is equal to the volume of the pebble.

∴ Volume of the pebble, V = 60 - 50 = 10 cm³

                                            = 10 × 10⁻⁶ m³

Weight of the pebble which is equivalent to mass is given as:

                                        M = 60 g

                                            = 60 × 10⁻³ Kg

Density of the pebble, D = M / V

                                         = (60 × 10⁻³) / (10 × 10⁻⁶)

                                  ∴ D = 6000 Kg/m³