Question

(3) The zeroes of the polynomial 3 x²+ 11x-4 (a)1/3,-4. (b) -1/3,4. (c) 1/3,4 (d) -1/3,-4​

Answer 1

Step-by-step explanation:

so,3x^2+11x-4=0

or,3x^2+12x-x-4=0

or,3x(x+4)-1(x+4)=0

or,(3x-1)(x+4)=0

so from here we get x=1/3,-4