Math, asked by subodhray3993, 6 months ago

3. The zeros of the polynomial p(x) =3x^2 -1 are.
(a)1/3 ands (b)1/5 3 and 3 (c)-1/ / sand / 3(d) 1/1 sand - 1/13
no fifth of its suni
fifth of its supplement. The measure of the angle is​

Answers

Answered by Anonymous
1

3. p(x) = 3x² - 1

sum of roots = -b/a = -0/3 = 0

products of roots = c/a = -1/3

Roots are = 0 and -1/3

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