Question

(3) Third
) First second
Second
(4) Zero
For the reaction, 2N205-> 4NO2 TO
1,06 -- 2NO, +202. Given,
rate - lN2051
d[N,05) K, IN,03]
d[NO2) = K2 [N205]
2k, = K2 =qk3.
1 dt a
d[O2] = K2 [N203]
and dt er
The relation between Ky, K, and Kz is
2k, = K₂ = 4K3 (2) K = K₂ = K₂
(3) 2K, = 4K, = K; NA K = 2K, = 4K,​

Answer 1

Answer:

not able to answer ur question

sryyy dear