3. Three coins are tossed simultaneously 100 times with the following frequencies of
different outcomes:
Outcome:
No head One head Two heads Three heads
Frequency:
14
38
36
12
If the three coins are simultaneously tossed again, compute the probability of:
(i) 2 heads coming up.
(ii) 3 heads coming up.
(ii) at least one head coming up. (iv) getting more heads than tails.
(v) getting more tails than heads.
1
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Answers
1) ' 2 heads ' outcome = 36
Total number of outcomes = 100
So, P [ 2 heads ] = 36 / 100
= 0.36
2) ' 3 heads ' outcome = 12
Total number of outcomes = 100
So, P [ 3 heads ] = 12 / 100
= 0.12
3) ' 1 or +1 heads ' outcome = 14 + 38 + 36 + 12
= 100
Total number of outcomes = 100
So, P [ 1 or +1 heads ] = 100 / 100
= 1
4) ' heads > tail ' outcome = 12
Total number of outcomes = 100
So, P [ head > tail ] = 12 / 100
= 0.12
5) ' heads < tail ' outcome = 14 + 38
= 52
Total number of outcomes = 100
So, P [ head < tail ] = 52 / 100
= 0.52