Question

3.
Three distinct numbers are given. The difference between the largest and the smallest is
added to the third number. One third of resultant number is less than the average of the
original three numbers by 14. Find the smallest number (among the original three numbers).
1) 42
2) 12
3) 21
4) Cannot be determined​

Answer 1

Step-by-step explanation:

plz refer the attachment

Answer 2

Answer:

21

Step-by-step explanation:

Let the nums be x, y & z. (x>y>z i.e z is smallest)

according to question,

difference of largest and smallest nums i.e. x-z is added to third (i.e. other) num.

Doing that we get,

ResultantNum = y + (x - z)

Now, again from question,

1/3 of ResultantNum = (avg. of x,y,z) - 14

=> (y + x - z)/3 = (x+y+z)/3 - 14

=> x + y - z = x + y + z - 42

=> 2z = 42

=> z = 21 i.e. smallest number.