3. Three numbers are in the ratio 3:4:5. If the sum of the largest and the smallest numbers exceeds the
third number by 64, find the numbers.
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Answer:
The no are 48,64,80
Step-by-step explanation:
Let the three numbers be 3x,4x and 5x
According to the question
5x+3x = 4x + 64
8x-4x = 64
4x = 64
x = 64/4
x = 16
=> 3x = 3×16 = 48
=> 4x = 4×16 = 64
=> 5x = 5×16 = 80
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