3 times a number added to 2 times another number gives 33.When 3 times the second number is subtracted from
4 times the first number gives 10. Find the numbers?
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Answer:
3x + 2y = 33 .......... 1
4x - 3y = 10 ........... 2
multiply the first equation with 3, we get
9x +6y = 99 .......... 3
multiply the second equation with 2, we get
8x - 6y = 20 ........ 4
subtract equation 4 from equation 3, we get
x = 79
substitute the value of x in equation 1, we get
y = 102
Step-by-step explanation:
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