Question

3 times the roots of 6x'-77+8x'-7x+2 =0​

Answer 1

Step-by-step explanation:

6x²7x-3=0

6x² - 9x + 2x - 3=0

3x (2x-3)+1(2x - 3)

(3x + 1)(2x - 3) = 0

3x + 1 = 0

3x = -1

-

and

2x - 30

82x = 3

X=

sum of zeroes = a +ß = ¹² + product of zeroes = aß= = x== -

6x²7x-3=0

6x² - 9x + 2x - 3=0

3x (2x-3)+1(2x - 3)

(3x + 1)(2x - 3) = 0

3x + 1 = 0

3x = -1

x = -1/3

and

2x - 30

82x = 3

X= 3/2

sum of zeroes = a +ß = ¹² + product of zeroes = aß= = x== -

coefficient of I

coefficient of x² constant term

coefficient of r²

coefficient of I

coefficient of x² constant term

coefficient of r²