3. To show AABC = A POR by SAS axiom, when AB =PQ = 3cm and BC= QR = 4cm,
then write the other necessary condition.
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In ΔABC and ΔPQR
AB=PQ
And BC=QR
CB And RQ extended to X and Y
∠ABX=∠PQY
∠ABC=180
o
−∠ABX=180
o
∠PQY
∠PQR=180
o
−∠PQY=∠ABC
We get in both triangles
AB=PQ
BC=QR
And ∠ABC=∠PQR
Then both triangle are congruent
i.e. ΔABC=ΔPQR
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